Existence of Loomis Optimisers
Compactness and continuity step for the Loomis induction (Direct Induction Proof Of Loomis Theorem): the Loomis ratios are continuous on the simplices, and their extrema are attained.
Setup
Fix $A, B \colon I \times J \to \mathbb{R}$ with $B$ entrywise positive (see Positive Aggregates xB and By). Define $$ \lambda_\mathrm{aux}(x) = \inf_{j \in J} \frac{(xA)_j}{(xB)_j}, \qquad \mu_\mathrm{aux}(y) = \sup_{i \in I} \frac{(Ay)_i}{(By)_i}, $$ and $$ \lambda_0 = \sup_{x \in \Delta(I)} \lambda_\mathrm{aux}(x), \qquad \mu_0 = \inf_{y \in \Delta(J)} \mu_\mathrm{aux}(y). $$
Statement
(i) Continuity. The maps $\lambda_\mathrm{aux} \colon \Delta(I) \to \mathbb{R}$ and $\mu_\mathrm{aux} \colon \Delta(J) \to \mathbb{R}$ are continuous.
(ii) Boundedness. $\lambda_\mathrm{aux}$ is bounded above and $\mu_\mathrm{aux}$ is bounded below on their respective simplices.
(iii) Attainment. There exist $x_0 \in \Delta(I)$ and $y_0 \in \Delta(J)$ such that $\lambda_\mathrm{aux}(x_0) = \lambda_0$ and $\mu_\mathrm{aux}(y_0) = \mu_0$. Equivalently, for every $j \in J$ and every $i \in I$, $$ (x_0 A)_j \ge \lambda_0\,(x_0 B)_j, \qquad (A y_0)_i \le \mu_0\,(B y_0)_i. $$
Proof
(i) Each coordinate $x \mapsto (xA)_j$ and $x \mapsto (xB)_j$ is a continuous linear functional on $\Delta(I)$. Their quotient is continuous because the denominator is strictly positive (Positive Aggregates xB and By). The finite infimum of continuous functions over the finite set $J$ is continuous. The argument for $\mu_\mathrm{aux}$ is dual.
(ii) Each ratio $(xA)_j / (xB)_j$ is bounded above by the obvious extreme $M_A / m_B$, where $M_A := \max_{i, j} A_{ij}$ and $m_B := \min_{i, j} B_{ij}
0$. So $\lambda_\mathrm{aux} \le M_A / m_B$. Symmetrically, $\mu_\mathrm{aux} \ge m_A / M_B$ where $m_A := \min_{i, j} A_{ij}$ and $M_B := \max_{i, j} B_{ij}$.
(iii) $\Delta(I)$ is compact in $\mathbb{R}^{|I|}$, and the continuous function $\lambda_\mathrm{aux}$ attains its supremum on a compact set (extreme-value theorem). Let $x_0$ be a maximiser; then $\lambda_\mathrm{aux}(x_0) = \lambda_0$, which by definition of the infimum-over-$j$ gives $(x_0 A)_j / (x_0 B)_j \ge \lambda_0$ for every $j$, i.e. $(x_0 A)_j \ge \lambda_0 (x_0 B)_j$ (multiplying by the strictly positive $(x_0 B)_j$). The $\mu_0$ side is dual.
The compact/continuous building blocks (Continuity on the Real Standard Simplex and Pointwise Bounds Are Simplex Bounds) live in the core simplex layer; this lemma extends the $B = \mathbf{1}$ case (Existence of Optimal Mixed Strategies (Loomis Foundations)) to general positive $B$ by composing with positive division. $\square$
References
- [MFoGT, Section 2.5] Laraki, Renault, and Sorin, Mathematical Foundations of Game Theory. Compactness step for the Loomis ratios.